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A trader bought two horses for Rs.19,500...

A trader bought two horses for Rs.19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each horse is the same, then their cost prices are respectively.

A

Rs.10,000 and Rs.9,500

B

Rs. 11,500 and Rs.8,000

C

Rs.12,000 and Rs.7,500

D

Rs.10,500 and Rs.9,000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will denote the cost prices of the two horses as follows: Let the cost price of the first horse be \( X \). Then, the cost price of the second horse will be \( 19500 - X \) (since the total cost price of both horses is Rs. 19,500). ### Step 1: Calculate the Selling Price of the First Horse The first horse is sold at a loss of 20%. The selling price (SP) of the first horse can be calculated as: \[ SP_1 = X - 0.20X = 0.80X \] Alternatively, this can be expressed as: \[ SP_1 = \frac{80}{100} \times X = \frac{80X}{100} \] ### Step 2: Calculate the Selling Price of the Second Horse The second horse is sold at a profit of 15%. The selling price of the second horse can be calculated as: \[ SP_2 = (19500 - X) + 0.15(19500 - X) = (19500 - X) \times \frac{115}{100} \] This can also be expressed as: \[ SP_2 = \frac{115}{100} \times (19500 - X) \] ### Step 3: Set the Selling Prices Equal Since the selling prices of both horses are the same, we can set the equations equal to each other: \[ 0.80X = \frac{115}{100} \times (19500 - X) \] ### Step 4: Clear the Fraction To eliminate the fraction, we can multiply both sides by 100: \[ 80X = 115(19500 - X) \] ### Step 5: Expand and Rearrange the Equation Expanding the right side gives: \[ 80X = 2235000 - 115X \] Now, add \( 115X \) to both sides: \[ 80X + 115X = 2235000 \] This simplifies to: \[ 195X = 2235000 \] ### Step 6: Solve for X Now, divide both sides by 195 to find \( X \): \[ X = \frac{2235000}{195} = 11400 \] ### Step 7: Calculate the Cost Price of the Second Horse Now that we have \( X \), we can find the cost price of the second horse: \[ \text{Cost Price of Second Horse} = 19500 - X = 19500 - 11400 = 8100 \] ### Final Result Thus, the cost prices of the two horses are: - Cost Price of the First Horse: Rs. 11400 - Cost Price of the Second Horse: Rs. 8100
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