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An article is marked at Rs. 5,000. The s...

An article is marked at Rs. 5,000. The shopkeeper allows successive discounts of x%, y%, z% on it. The net selling price is

A

Rs `((100-x)(100+y)(100+z))/(200)`

B

Rs `((100+x)(100+y)(100-z))/(200)`

C

Rs `((100-x)(100-y)(100-z))/(200)`

D

Rs `((100-x)(100+y)(100-z))/(200)`

Text Solution

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The correct Answer is:
To find the net selling price of an article after successive discounts, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Marked Price**: The article is marked at Rs. 5000. 2. **Understand Successive Discounts**: The shopkeeper gives successive discounts of x%, y%, and z%. This means that after each discount, the new price becomes the base for the next discount. 3. **Calculate the Selling Price After Each Discount**: - After the first discount of x%, the selling price (SP1) can be calculated as: \[ SP1 = \text{Marked Price} \times \left(1 - \frac{x}{100}\right) = 5000 \times \left(1 - \frac{x}{100}\right) \] - After the second discount of y%, the selling price (SP2) becomes: \[ SP2 = SP1 \times \left(1 - \frac{y}{100} \right) = 5000 \times \left(1 - \frac{x}{100}\right) \times \left(1 - \frac{y}{100}\right) \] - After the third discount of z%, the final selling price (SP3) is: \[ SP3 = SP2 \times \left(1 - \frac{z}{100} \right) = 5000 \times \left(1 - \frac{x}{100}\right) \times \left(1 - \frac{y}{100}\right) \times \left(1 - \frac{z}{100}\right) \] 4. **Simplifying the Expression**: - The final selling price can be expressed as: \[ SP = 5000 \times \left(1 - \frac{x}{100}\right) \times \left(1 - \frac{y}{100}\right) \times \left(1 - \frac{z}{100}\right) \] - This can also be written as: \[ SP = \frac{5000 \times (100 - x)(100 - y)(100 - z)}{100^3} \] 5. **Final Result**: - Therefore, the net selling price after the successive discounts is: \[ SP = \frac{5000 \times (100 - x)(100 - y)(100 - z)}{100^3} \]
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