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If (x + 7954 xx 7956) be a square number...

If `(x + 7954 xx 7956)` be a square number, then the value of x is

A

1

B

16

C

9

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( x \) such that \( x + 7954 \times 7956 \) is a perfect square. ### Step-by-step Solution: 1. **Understand the Expression**: We need to analyze the expression \( x + 7954 \times 7956 \). First, we calculate \( 7954 \times 7956 \). 2. **Calculate \( 7954 \times 7956 \)**: We can use the difference of squares: \[ 7954 \times 7956 = (7955 - 1)(7955 + 1) = 7955^2 - 1^2 = 7955^2 - 1 \] 3. **Substitute Back into the Expression**: Now, substitute this back into the expression: \[ x + 7954 \times 7956 = x + (7955^2 - 1) = x + 7955^2 - 1 \] 4. **Set the Expression Equal to a Perfect Square**: We want this expression to be a perfect square, so we set: \[ x + 7955^2 - 1 = y^2 \] Rearranging gives: \[ x = y^2 - 7955^2 + 1 \] 5. **Use the Difference of Squares**: The expression \( y^2 - 7955^2 \) can be factored: \[ y^2 - 7955^2 = (y - 7955)(y + 7955) \] Therefore: \[ x = (y - 7955)(y + 7955) + 1 \] 6. **Finding Suitable Values for \( y \)**: For \( x \) to be a non-negative integer, \( y \) must be chosen such that \( (y - 7955)(y + 7955) \) is a non-negative integer. 7. **Choose \( y = 7955 + 1 \)**: Let’s try \( y = 7956 \): \[ x = (7956 - 7955)(7956 + 7955) + 1 = (1)(15911) + 1 = 15911 + 1 = 15912 \] 8. **Final Value of \( x \)**: Thus, the value of \( x \) that makes the expression a perfect square is: \[ x = 1 \] ### Conclusion: The value of \( x \) is \( \boxed{1} \).
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