The displacement `xi` in centimetres of a particle is `xi = 3 sin 314 t + 4 cos 314 t`. Amplitude and initial phase are

The displacement of a particle performing S.H.M. is x = 3 sin (314 t) + 4 cos (314 t). Then the initial phase angle is,

The displacement eqution of a particle is x=3 sin 2t + 4 cos 2t . The amplitude and maximum velocity will be respetively

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement equation of a particle is x=3 sin 2t+4cos2t . The amplitude and maximum velocity will be respectively

The displacement equation of a particle is x=3 sin 2t+4cos2t . The amplitude and maximum velocity will be respectively

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The displacement of a particle performing S.H.M. is, x = 3 sin (314t) + 4 cos (314t), where x and t are in CGS units. Then the amplitude of the S.H.M. is,