यदि `tan (alpha +theta)=n tan (alpha-theta)`, तो सिद्ध कीजिए की-
`(n+1) sin 2 theta=(n-1) sin 2 alpha`

If tan (alpha + theta) = n tan(alpha - theta) , show that : (n + 1) sin 2 theta = (n - 1) sin 2alpha .

If tan (alpha + theta ) = n* tan ( alpha - theta ) , "then " (n +1) sin 2 theta =

If tan (alpha+theta)=n tan (alpha-theta) ,show that: (n+1)"sin" 2theta=(n-1) sin 2alpha

If tan(alpha+theta)=n tan(alpha-theta), show that (n+1)sin2 theta=(n-1)sin2 alpha.

If "tan"(alpha+theta)=n "tan"(alpha-theta) ,ahow that: (n+1)"sin"2 theta=(n-1)"sin"2alpha

If tan(alpha+theta)=ntan(alpha-theta) , show that: (n+1)sin 2theta=(n-1)sin2alpha .

If tan(alpha+theta)=ntan(alpha-theta) , show that (n+1)sin2theta=(n-1)sin2alphadot

If tan(alpha+theta)=n tan(alpha-theta) then value of (n+1)/(n-1)=

If tan theta = ( tan alpha + tan beta)/(1 + tan alpha tan beta),"show that " sin 2 theta =(sin 2 alpha + sin 2 beta)/(1+sin 2 alpha sin 2 beta)