A small ball (mass m) falling under gravity in a viscous medium experience a drag force proportional to the instantaneous speed u such that `F_(drag)=ku`. Then the terminal speed of ball within viscous medium is

A spherical body of diameter D is falling in viscous medium. Its terminal velocity is proportional to

A small spherical ball falling under gravity in a viscous medium heat the medium due to viscous drage force. The rate of heating is proportional to r^(n) . ( r= radius of the sphere find ) n .

A ball of mass m and radius r is released in a viscous liquid. The value of its terminal velocity is proportional to

A ball of mass m and radius r is released in a viscous fluid. The value of its terminal velocity is proportional to

A small spherical body of radius r is falling under gravity in a viscous medium. Due to friction the meduim gets heated. How does the rate of heating depends on radius of body when it attains terminal velocity?

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)