Evaluate: `(1002)^3`

Evaluate : [ ( 1 )^3 ]^(-3) = ----

Find the value of (1002)^((1)/(3))

The value of (1.002)^12 up to 4th place of decimal

Evaluate : ((3)/(7))^(3)

Evaluate (14)^(3)+(-8)^(3)+(-6)^(3) .

Evaluate: 25^3-75^3+50^3

Evaluate: 48^3-30^3-18^3

Using differentials, find the approximate value of (log)_e 10.02 , it being given that (log)_e 10=2. 3026 .