Show that projection angle `theta_(0)` for a projectile launched from the origin is given by:
`theta_(0)=tan^(-1)[(4H_(m))/(R)]` Where `H_(m)=` Maximum height, R=Range

Shown that for a projectile the angle between the velocity and the x-axis as a function of time is given by theta(t)=tan^(-1)((v_(oy)-gt)/(v_(ax))) (b) Show that the projection angle theta_(0) for a projectile lauched from the origin is given by theta_(0)=(tan^(-1)(4h_(m))/(R)) Where the symbols have their usual meaning.

Show that the projection angle theta_0 for a projectile launched from the origin is given by theta_0=tan^(-1)((4H)/R) Where the symbols have their usual meaning.

(a) Show that for a projectile the angle between the velocity and the x - axis as a function of time is given by theta(t)="tan"^(-1)((v_(0y)-"gt")/(v_(@)x)) (b) Shows that the projection angle theta_(@) for a projectile launched from the origin given by theta_(0)=tan^(-1)((4h_(m))/(R)) where the symbols have their usual meaning.

(a) Show that for a projectile the angle between the velocity and the x - axis as a function of time is given by theta(t)="tan"^(-1)((v_(0y)-"gt")/(v_(@)x)) (b) Shows that the projection angle theta_(@) for a projectile launched from the origin given by theta_(0)=tan^(-1)((4h_(m))/(R)) where the symbols have their usual meaning.

(a) Show that for a projectile the angle between the velocity and the x - axis as a function of time is given by theta(t)="tan"^(-1)((v_(0y)-"gt")/(v_(@)x)) (b) Shows that the projection angle theta_(@) for a projectile launched from the origin given by theta_(0)=tan^(-1)((4h_(m))/(R)) where the symbols have their usual meaning.

Show that the projection angle thetha_0 for a projectile launched from the origin is given by theta_0 =tan^1(4h_m//R) Where the symbols have their usual meaning.

Shows that the projection angle theta_o for a projectile launched from the origin is given by theta_o=tan^-1((4h_m)/R) where the symbols have their usual meaning.

Show that for a projectile the angle between the velocity and the x-axis as function of time is given by theta_(t) = tan ^(-1)( ( v_(0 y)-g t)/(v_(o x))) (b) Shows that the projection angle theta_0 for a projectile launched from the origin is given by theta_(t) = tan ^(-1)( ( 4 h_m)/R) where the symbols have their usual meanings.