A metal wire has a resistances of `5 Omega` . If its length is doubled by stretching,what would be its resistance? Suppose the volume and resistivity of the wire do not change.

A metal wire has a resistance of 35Omega . If its length is increased to double by drawing it, then its new resistance will be

A metal wire has a resistance of 35Omega . If its length is increased to double by drawing it, then its new resistance will be

A metallic wire has a definite resistance . IF the wire is stretched in such a way that its length becomes doubled then what will be the resistance of the wire? Consider the volume and the resistivity of the wire remains unchanged.

A wire has resistance 5Omega . If it is stretched to increase the Length by 10% then what will be its final resistance?

A wire has resistance of 10Omega . If it is stretched by 1/10th of its length, then its resistance is nearly

The resistance of a wire is R . If the length of the wire is doubled by stretching, then the new resistance will be

A wire has a resistance of 10Omega . It is stretched by 1//10 of its original length. Then its resistance will be

A wire has a resistance of 10Omega . It is stretched by 1//10 of its original length. Then its resistance will be

A given wire of resistance 1 Omega is stretched to double its length. What will be its new resistance ?