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(3+sqrt(5))^n-3[((3+sqrt(5))^n)/3]...

`(3+sqrt(5))^n-3[((3+sqrt(5))^n)/3]`

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If n is a positive integer and U_(n) = (3 + sqrt5)^(n) + (3 - sqrt5)^(n) , then prove that U_(n + 1) = 6U_(n) - 4U_(n -1), n ge 2

(7+3sqrt(5))/(3+sqrt(5))+(7-3sqrt(5))/(3-sqrt(5))

Find the value of a and b if (7+3sqrt(5))/(3+sqrt(5))-(7-3sqrt(5))/(3-sqrt(5)) =a + bsqrt(5)

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The value of (7+3 sqrt5)/(3+sqrt5)-(7-3 sqrt5)/(3-sqrt5) lies between: (7+3 sqrt5)/(3+sqrt5)-(7-3 sqrt5)/(3-sqrt5) का मान किसके बीच में होगा

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(sqrt(3)-sqrt(5))(sqrt(5)+sqrt(3))

The sum up to n terms of the series 1/(sqrt(1) + sqrt(3)) + 1/(sqrt(3) + sqrt(5)) + 1/(sqrt(5) + sqrt(7)) +… is:

If sum_(i=1)^n(x_i+1)^2=9n and sum_(i=1)^n(x_i-1)^2=5n , then standard deviation of these 'n' observations (x_1) is: (1) 2sqrt(3) (2) sqrt(3) (3) sqrt(5) (4) 3sqrt(2)