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(sin3A+sin5A+sin7A+sin9A)/(cos3A+cos5A+c...

`(sin3A+sin5A+sin7A+sin9A)/(cos3A+cos5A+cos7A+cos9A)`

Answer

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Prove that: (sin3A+s in5As in7A+s in9A)/(cos3A+cos5A+cos7A+cos9A)=tan6A

Prove that: (sin7A+sin5A+sin9A+sin3A)/(cos3A+cos5A+cos7A+cos9A)= tan6A

Knowledge Check

  • ( sin A + sin 5A + sin 9A)/( cos A + cos 5A + cos 9A)=

    A
    `tan 2A `
    B
    `tan 3 A `
    C
    `tan 4A `
    D
    `tan 5A `

  • (sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A) is :

    A
    `tan 2A`
    B
    `tan3A`
    C
    `tan4A`
    D
    `tan8A`

    • Similar Questions

    Explore conceptually related problems

    Prove that: (sin7A+sin5A+sin9A+sin3A)/(cos3A+cos5A+cos7A+cos9A)= tan6A

    (sin A + sin5A + sin9A) / (cos A + cos5A + cos9A) =

    Prove that: (sin2A sin3A-sin4A sin5A+sin3A sin6A)/(cos2A cos3A-cos4A cos5A+cos3A cos6A)=tan A tan4A

    (sin A-sin5A+sin9A-sin13A)/(cos A-cos5A-cos9A+cos13A)=cot4A

    (sin A-sin5A+sin9A-sin13A)/(cos A-cos5A-cos9A+cos13A)=cot4A

    (sin A+sin3A+sin5A+sin7A)/(cos A+cos3A+cos5A+cos7A)=tan4A

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