Finf the wavelength of the first line of the `HE^(+)`ion spectral series whose interval between the extreme line is `Delta omega= 5.18.10^(15) s^(-1)`.

Find the wavelenght of the first line of He^(+) ion sepectral series whose interval between extreme line is [(1)/(lambda)-(1)/(lambda)=2.745xx10^(4)cm^(1)]

Find out the wavelength of the first line of the He+ ion in a spectral series whose frequency width is Deltav=3.3xx10^(15)s^(-1)

The wavelength of the first spectral line of the Lyman series of hydrogen spectrum is

Wavelength of the first line of Paschen series is - (R = 109700 cm^-1 )

If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

Calculate the wavelength of the first spectral line in the corresponding Lyman series of the hydrogen atom.

Ratio of the wavelengths of first line of Lyman series and first line of Balmer series is 5 : X then find X.

Ratio of the wavelengths of first line of Lyman series and first line of Balmer series is 5 : X then find X.