Given `y = f(u) and u = g(x).` Find `(dy)/(dx)`.
`y = sin u, u = 3x + 1`

Given y=f(u) and u=g(x) Find (dy)/(dx) if y=2u^(3),u=8x-1

Find dy/dx if : y = 9u^2, u = 1 - 3/2x^2

U=x^y find (dU)/dx

If y = (u -1)/(u + 1) and u = sqrt(x) , then (dy)/(dx) is

If y = (u -1)/(u + 1) and u = sqrt(x) , then (dy)/(dx) is

If y=2+sqrtu and u=x^(3)+1 , then (dy)/(dx)=

Find dy/dx when y = sin u, u = e^(sqrtt) and t = log x

If y = f(u) is a differentiable functions of u and u = g(x) is a differentiable functions of x such that the composite functions y = f[g(x) ] is a differentiable functions of x then (dy)/(dx) = (dy)/(du) . (du)/(dx) Hence find (dy)/(dx) if y = sin ^(2)x

find (dy)/(dx) , when y = sin u ,, u = e^(sqrt t) and t = log x

find (dy)/(dx) , when y = sin u ,, u = e^(sqrt t) and t = log x