The displacement of a body is given by `s=(1)/(2)g t^(2)` where g is acceleration due to gravity. The velocity of the body at any time t is

The displacement of a body is given by 2 s= g t^(2) where g is a constant. The velocity of the body at any time t is :

The height reached in time t by a particle thrown upward with a speed u is given by h=ut-(1)/(2) "gt"^(2) where g is acceleration due to gravity. Find the time taken in reaching the maximum height.

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of body is given by s = 4 + 2t^4 . The acceleration of the body at the end of 1 s from the start is :

The displacement of a body is given by r=sqrt(a^(2)-t^(2))+t cost^(2) , where t is the time and a is constant. Its velosity is :

The displacement of a body is given by r=sqrt(a^(2)-t^(2))+t cost^(2) , where t is the time and a is constant. Its velosity is :

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after: