heat of neutralisation of HCl against NaOH is 13.7 kcal `eq^(-1)` what will be the ionisation energy of `CH_(3)COOH` in kcal `mol^(-1)` if its heat of neutralisation is 11.7 kcal `eq^(-1)`.

Heat of neutralisation of CH_3COOH_((aq)) with NaOH_((aq)) is - 55.2kJ. What is heat of ionisation of CH_3COOH ?

The enthalpy of neutralisation of NH_(4)OH and CH_(3)COOH is -10.5 kcal mol^(-1) and enthalpy of neutralisation of CH_(3)COOH with strong base is -12.5 kcal mol^(-1) . The enthalpy of ionisation of NH_(4)OH will be

Heat of neutralization between HCl and NaOH is -13.7 k.cal . If heat of neutralization between CH_(3)COOH and NaOH is -11.7 k.cal . Calculate heat of ionization of CH_(3)COOH .

Heat of neutralization of HCl by NaOH is 13.7 kcal per equivalent and by NH_4OH is 12.27 kcal. The heat of dissociation of NH_4OH is