Home
Class 12
MATHS
3x+b =5x-7 3y + c= 5y-7 In the equat...

`3x+b =5x-7`
`3y + c= 5y-7`
In the equation above, b and c are constants. If b is c minus `1/2`, which of the following is true?

Promotional Banner

Similar Questions

Explore conceptually related problems

2x+p=7x-3, 2y+q=7y-3 In the above equations, p and q are constant. If q is 5 less than p, which of the following statements is true?

2x(3x+5)+3(3x+5)=ax^(2)+bx+c In the equation above, a, b, and c are constants. If the equation is true for all values of x, what is the value of b ?

If a = 3x - 5y, b = 6x + 3y and c = 2y - 4x . Find : (i) a + b - c , (ii) 2a - 3b + 4c .

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

If the co-ordinates of A and B are (1,1)and (5,7), then the equation of the perpendicular bisector of the line segment AB is............... A) 2x+3y=18 B) 2x-3y+18=0 C) 2x+3y-1=0 D) 3x-2y+1=0

Form the differential equations by elimniating the arbitary constants from the following equations : (1) y =c^(2)+c/x (2) x^(3) +y^(3) = 4ax (3) y = Ae^(5x) + Be^(-5x) (4) y = A cos alpha x + B sin alpha x