If two chords of a circle intersect inside or outside the circle when produced ; the rectangle formed by the two segments of one chord is equal in area to the rectangle formed by the two segments of the other chord.

Theorem of internal division of chords. Suppose two chords of a circle intersect each other in the interior of the circle, then the product of the lengths of the two segments of one chord is equal to the product of the lengths of the two segments of the other chord. Given : (1) A circle with centre O . (2) chords PR and QS intersect at point E inside the circle. To prove : PE xx ER = QE xx ES Construction : Draw seg PQ and seg RS

If two chords of a circle intersect internally, then the rectangle of two parts of one is equal to the rectangle of two parts of other.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to correspondig segments of the other chord.

If two equal chords of a circle intersect within the circle,prove that the segments of one chord are equal to corresponding segments of the other chord.