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The standard enthalpy and entropy change...

The standard enthalpy and entropy changes for the reaction in equilibrium for the forward direction are given below:
`CO(g) +H_(2)O(g) hArr CO_(2)(g) +H_(2)(g)`
`DeltaH^(Theta)underset(300K). =- 41.16 kJ mol^(-1)`
`DeltaS^(Theta)underset(300K). =- 4.14 xx 10^(-2) kJ mol^(-1)`
`DeltaH^(Theta)underset(1200K). =- 31.93 kJ mol^(-1)`
`DeltaH^(Theta)underset(1200K). =- 2.96 xx 10^(-2) kJ mol^(-1)`
Calculate `K_(p)` at each temperature and predict the direction of reaction at `300K` and `1200k`, when `P_(CO) = P_(CO_(2)) =P_(H_(2)) = P_(H_(2)O) =1` atm at initial state.

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The standard enthalpy and entropy changes for the reaction in equilibrium for the forward direction are given below: CO_((g))+H_(2)O_((g))hArrCO_(2(g))+H_(2(g)) DeltaH_(300K)^(@)=-41.16 kJ mol^(-1) DeltaS_(300 K)^(@)=-4.24xx10^(-2) kJ mol^(-1) DeltaH_(1200 K)^(@)=-32.93 K J mol^(-1) DeltaS_(1200 K)^(@)=-2.96xx10^(-2) k J mol^(-1) Calculate K_(p) at each temperature and predict the direction of reaction at 300 K and 1200 K , when P_(CO)=P_(CO_(2))=P_(H_(2))=P_(H_(2)O)=1 atm at initial state.

For the reaction: CO(g) +H_(2)O(g) hArr CO_(2)(g) +H_(2)(g) (Delta_(r)H)_(300K) = - 41.2 kJ mol^(-1) (Delta_(r)H)_(1200K) =- 33.0 kJ mol^(-1) (Delta_(r)S)_(300K) = - 4.2 xx 10^(-2) kJ mol^(-1) (Delta_(r)S)_(1200K) =- 3.0 xx10^(-2) kJ mol^(-1) Predict the direction of spontaneity of the reaction at 300K and 1200K . also calculated log_(10)K_(p) at 300K and 1200K .

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What is the equilibrium constant K_(c) for the following reaction at 400K ? 2NOCI(g) hArr 2NO(g) +CI_(2)(g) DeltaH^(Theta) = 77.2 kJ mol^(-1) and DeltaS^(Theta) = 122 J K^(-1) mol^(-1) at 400K .

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Calculate equilibrium constant for the reaction: 2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) at 25^(@)C Given: Delta_(f)G^(Theta) SO_(3)(g) = - 371.1 kJ mol^(-1) , Delta_(f)G^(Theta)SO_(2)(g) =- 300.2 kJ mol^(-1) and R = 8.31 J K^(-1) mol^(-1)

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Calculated the equilibrium constant for the following reaction at 298K : 2H_(2)O(l) rarr 2H_(2)(g) +O_(2)(g) Delta_(f)G^(Theta) (H_(2)O) =- 237.2 kJ mol^(-1),R = 8.314 J mol^(-1) K^(-1)

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