Water at Bhakra dam falls through a height of 210 m. Assuming that the whole of the energy due to fall is converted into heat, calculate the rise in temperature of water. Take `J = 4.2 J cal^(-1)` and `g = 9.8 ms^(-2)`.

A water fall is 84 m high. Assuming that half the kinetic energy of falling water get converted to heat, the rise in temperature of water is

Calculate the rise in temperature of water, which falls from a height of 100m. Assume that 80% of the energy due to fall is converted into heat and is retaied by the water. J = 4.2 xx 10^(7) erg cal^(-1) .

In a water-fall the water falls from a height of 100 m . If the entire K.E. of water is converted into heat, the rise in temperature of water will be

Water drops from a height of 40 m in a waterfall. if 75% of its energy is converted into heat and absorbed by the water, the rise in temperature of the water will be

Water fall from a height 50m, If one third of its mechanical energy converted into heat what will be the rise in temperature of water

The height of a waterfall is 84 metre . Assuming that the entire kinetic energy of falling water is converted into heat, the rise in temperature of the water will be ( g=9.8 m//s^(2),J=4.2 joule / cal)

Calculate the difference in temperature between the water at the top and bottom of Niagra falls of height 500 m assuming that the whole K.E. due to fall is converted into heat. Specific beat capacity of water 4200 Jkg ^(-1) K ^(-1).