Home
Class 12
Chemistry
Visha took two aqueous solutions, one co...

Visha took two aqueous solutions, one containing 7.5 g of urea (Molar mass = 60 g/mol) and the other containing 42.75 g of substance Z in 100 g of water, respectively. It was observed that both the solutions froze at the same temperature. Calculate the molar mass of Z.

Promotional Banner

Similar Questions

Explore conceptually related problems

The aqueous solutions containing respectively 7.5 g of urea (molar mass=60) and 42.75 g of substance X in 100 g of water freeze at the same temperatuer. Calculate the molecular weight of X.

What is the molality of a solution containing 200 mg of urea (molar mass = 60 g mol^(-1) ) in 40g of water ?

Two aqueous solution containing, respectively, 7 g urea (molar mass = 60 g) and 42 g of substance X in 100 g of water freeze at the same temperarture. Calculate the molecular weight of X .

Two aqueous solution containing, respectively, 7 g urea (molar mass = 60 g) and 42 g of substance X in 100 g of water freeze at the same temperarture. Calculate the molecular weight of X .

Two aqueous solution containing, respectively, 7 g urea (molar mass = 60 g) and 42 g of substance X in 100 g of water freeze at the same temperarture. Calculate the molecular weight of X .

The molarity of solution containing 15.20 g of urea, (molar mass = 60) dissolved in 150 g of water is

The molarity of solution containing 15.20 g of urea, (molar mass = 60) dissolved in 150 g of water is

Calculate the molality of an aqueous solution containing 3.0g of urea (mol.mass=60) in 250g of water.