`inte^(alog_e x) dx`

choose the correct answer from the given alternatives : the value of int e ^(alog_e x) dx will be-

If a gt0 and a!=1 evaluate the following integrals: (i) int e^(xlog_(e)a)dx (ii) int e^(alog_(e)x)dx (iii) int e^x a^xdx (iv) int 2^(log_(e)x)dx

The value of inte^(aloge^x)dx will be

Evaluate: inte^(xlog_ea)+e^(alog_ex)+e^(alog_ea)\ dx

int e^(x log a) e^(x)dx=

int e^x sec e^x dx

int e^(x log a).e^(x) dx =

int(e^x)/(a+e^(x))dx=?

int e^(x)sec e^(x)dx