prove that `(106)^85-(85)^106` is divisible by `7`

(-1)^106 =

Evaluate (106)^3

Assertion: If 35 and 85 is divisible by 5, then, their sum 35 +85, is divisible by 5. Reason : If a number is a factor of two given numbers, then it is the factor of their sum.

( 2^(106))/(53) Find R .

85^(2)