The radius of the circle, having centre at `(2, 1)`, whose one of the chord is a diameter of the circle `x^2 + y^2-2x-6y + 6 = 0 `

The radius of the circle having centre at (2, 1) whose one of the chords is a diameter of the circle :

The radius of the circle having centre at (2,1) whose one of the chords is diameter of the circle x^2 + y^2 - 2x - 6y + 6 = 0 is

The radius of the circel, having centre at (2,1) whose one of the chord is a diameter of the circel x^(2) +y^(2) -2x -6y +6=0 is-

The radius of circle having centre at (2,1) and whose on of the chord is diameter of the circle x^(2)+y^(2)-2x-6y+6=0 is

The radius of the circle with centre at (3, 2) and whose common chord with the cirlce C:x^(2)+y^(2)-4x-8y+16=0 is also a diameter of the circle C, is

The radius of the circle with centre at (3, 2) and whose common chord with the cirlce C:x^(2)+y^(2)-4x-8y+16=0 is also a diameter of the circle C, is

Find the equation of the circle the end points of whose diameter are the centres of the circle : x^2 + y^2 + 6x - 14y=1 and x^2 + y^2 - 4x + 10y=2 .

Find the equation of the circle the end points of whose diameter are the centres of the circle : x^2 + y^2 + 6x - 14y=1 and x^2 + y^2 - 4x + 10y=2 .

Find the centre and radius of the the circles: x^2 +y^2 - 4x-6y-14=0

The centres of similutude of the circles x^(2)+y^(2)-2x-6y+6=0, x^(2)+y^(2)=1 is