Moment of inertia of a solid about its geometrical axis is given by `1 =2/5 MR^(2)` where M is mass & R is radius. Find out the rate by which its moment of inertia is changing keeping dnsity constant at the moment `R= 1 m`, `M=1 kg` & rate of change of radius w.r.t. time `2 ms^(-1)`

Prove that moment of inertia of uniform ring of mass M and radius R about its geometric axis is MR^(2)

The moment of inertia of a uniform circular disc about a tangent in its own plane is 5/4MR^2 , where M is mass and R is the radius of the disc. Find its moment of inertia about an axis through its centre and perpendicular to its plane.

Moment of inertia of a hollow cylinder of mass M and radius r about its own axis is

The moment of inertia of a solid sphere about an axis passing through the centre radius is 2/5MR^(2) , then its radius of gyration about a parallel axis t a distance 2R from first axis is

If the moment of inertia of a solid sphere of mass M and radius R is (2)/(5) MR^(2) , what will be the radius of gyration?.

The moment of inertia of a solid sphere about an axis passing through the centre radius is 1/2MR^(2) , then its radius of gyration about a parallel axis t a distance 2R from first axis is

(a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be 2 MR^(2)//5, where M is the mass of the sphere and R is the radius of the sphere. (b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be (1)/(4)MR^(2) , find the moment of inertia about an axis normal to the disc passing through a point on its edge.