A magnetising field of `1500""(A)/(m)` produces a magnetic flux density of `0.48 Wb//m^(2) ` in a iron bar . Calculate permeability of iron bar used .

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

A magnetising field intensity of 1000 A/m produces a magnetic flux density 0.25 (Wb)/ m^2 in a ferromagnetic substance. The relative permeability of ferromagnetic substance is (Approximately)

A magnetising field intensity of 1000 A/m produces a magnetic flux density 0.25 (Wb)/ m^2 in a ferromagnetic substance. The relative permeability of ferromagnetic substance is (Approximately)

A magnetizing field of 360A//m produces a magnetic flux density B = 0.6T in a ferromagnetic material. What is its permeability in TmA^-1 ?

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator