`2 2/3+3 1/2=`

Check whether the following numbers are in proportion or not : 2, 2(1)/(2), 3, 3 (1)/(2)

1 (2)/(3) + 2 (1)/(3) + 2 (2)/(3) - 4 (1)/(2) =

The value of 1-1/2(2/3)+1/3(2/3)^(2)-1/4(2/3)^(3)+... is

The sum of (1/2 . 2/2)/(1^3) + (2/2 . 3/2)/(1^3 + 2^3) + (3/2 . 4/2)/(1^3 + 2^3 + 3^3) + ….. Upto n terms is equal to

log_(1//2).(2)/(3) ______ log_(2//3) .(1)/(2) . The appropriate symbol in the blank is

If 1/1^3 + (1+2)/(1^3+2^3)+(1+2+3)/(1^3+2^3+3^3) +.......n terms then lim_(n->oo) [S_n]

((1)/(2), (2)/(2) )/(1^3) + ((2)/(2) , (3)/(2) )/( 1^3 + 2^3) + ((3)/(2) , (4)/(2) ) / (1^(3) + 2^(3) + 3^(3) ) + ..... n terms

If A=[[1, 2, 3], [2, -1, 3], [1, 2, 3]] , then

((1)/(2) . (2)/(2))/(1^(3))+((2)/(3) . (3)/(2))/(1^(3)+2^(3)) +((3)/(2) . (4)/(2))/(1^(3)+2^(3)+3^(3))+.. . . to n terms