`int(e^x+1/(e^n))^2`

Compute the following integrals: int(e^x+e^(-x))/(e^x-e^(-x)) dx or int(e^(2x) +1)/(e^(2x)-1)dx

int(e^(2x) -1)/(e^(2x) + 1) dx

(i) int (e^x dx)/(e^x (e^x-1)) (ii) int e^x/((1+e^x)(2+e^x)) dx (iii) int e^x/((e^x-1)^2(e^x+2)) dx

int(e^x)/((1+e^x)(2+e^x))dx

int(e^x)/((1+e^x)(2+e^x))dx

Evaluate int(e^(2x)+1)/(e^(2x)-1)

int(e^(2x)-1)/(e^(2x)+1)dx=...

int (e^(2x)-1)/(e^(2x)+1) dx=?

int(e^(2x)+1)/(e^(2x)-1)dx=

Column I, a) int(e^(2x)-1)/(e^(2x)+1)dx is equal to b) int1/((e^x+e^(-x))^2)dx is equal to c) int(e^(-x))/(1+e^x)dx is equal to d) int1/(sqrt(1-e^(2x)))dx is equal to COLUMN II p) x-log[1+sqrt(1-e^(2x)]+c q) log(e^x+1)-x-e^(-x)+c r) log(e^(2x)+1)-x+c s) -1/(2(e^(2x)+1))+c