In the following figure, `angle ABC =90^@ , AD=15` and `DC=20`.If BD is the bisector of `angle ABC `, What is the perimeter of the triangle ABC?

Construct angle ABC=90^(@) . Draw BP, the bisector of angle ABC. State, the measure of angle PBC.

In the given figure, angle ABC=90^(@) and BD bot AC . If BD=8 cm, AD=4 cm find CD.

In a Delta ABC it is given that AB=6 cm, AC=8 cm and AD is the bisector of angle A . Then BD:DC=?

In a triangle ABC, the angle bisector BD of angleB intersects AC in D. Suppose BC=2, CD=1 and BD=(3)/(sqrt(2)) . The perimeter of the triangle ABC is

In a Delta ABC, angleA = 90^@, angle C =55^@ and AD _|_BC . What is the value of angle BAD ?