Two particles move at right angle to each other.Their de Broglie wavelengths are lambda_(1) and lambda_(2) respectively.The particles suffer perfectly inelastic collision.The de Broglie wavelength lambda of the final particle is given by :

Two particles move at right angle to each other. Their de Broglie wavelenghts are lambda_(1) and lambda_(2) respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelenght lambda , of the final particle, is given by:

The de Broglie wavelength lambda of a particle

The de-Broglie wavelength lambda

de-Broglie wavelength lambda is

De Broglie wavelength lambda is proportional to

De Broglie wavelength lambda is proportional to

The de Broglie wavelength associated with particle is

The de Broglie wavelength associated with particle is