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Point P(p ,0),Q(q ,0),R(0, p),S(0,q) fro...

Point `P(p ,0),Q(q ,0),R(0, p),S(0,q)` from parallelogram rhombus cyclic quadrilateral (d) none of these

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Point P(p ,0),Q(q ,0),R(0, p),S(0,q) from (a)parallelogram (b)rhombus (c)cyclic quadrilateral (d) none of these

Point P(p ,0),Q(q ,0),R(0, p),S(0,q) form (a) parallelogram (b) rhombus (c) cyclic quadrilateral (d) none of these

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Consider the points P(p,0,0),Q(0,q,0) and R(0,0,r) where pqr!=0 then the equation of the plane PQR is (A) px+qy+r=1 (B) x/p+y/q+z/r=1 (C) x+y+z+1/p+1/q+1/r=0 (D) none of these

Consider the points P(p,0,0),Q(0,q,0) and R(0,0,r) where pqr!=0 then the equation of the plane PQR is (A) px+qy+r=1 (B) x/p+y/q+z/r=1 (C) x+y+z+1/p+1/q+1/r=0 (D) none of these

If p+q+r=0=a+b+c , then the value of the determinant |[p a, q b, r c],[ q c ,r a, p b],[ r b, p c, q a]|i s (a) 0 (b) p a+q b+r c (c) 1 (d) none of these

If p+q+r=0=a+b+c , then the value of the determinant |[p a, q b, r c],[ q c ,r a, p b],[ r b, p c, q a]|i s (a) 0 (b) p a+q b+r c (c) 1 (d) none of these

Prove that the figure formed by joining the mid-points of the pair of consecutive sides of a quadrilateral is a parallelogram. OR ABC D is a parallelogram in which P ,Q ,R and S are mid-points of the sides A B ,B C ,C D and D A respectively. A C is a diagonal. Show that : P Q|| A C and P Q=1/2A C S R || A C and S R=1/2A C P Q=S R (iv) P Q R S is a parallelogram.