A body is projected vertically upwards with some velocity `u`. It at the same point at `t = 6 s` as was at `t = 4 s`. Find the value of `u`.

A body is projected in vertically upwards direction with a speed u. Find the time taken

A body projected vertically upwards with a velocity of u returns to the starting point in 6 second, If g= 9,8 m s^-2 the value of 'u' is

A body projected vertically upwards with a velocity u returns to the starting point in 4 seconds. If g = 10m//sec , the value of u is

A body projected vertically with a velocity 'u' from ground. Its velocity

A player throws a ball vertically upwards with velocity u. At highest point,

A player throws a ball vertically upwards with velocity u. At highest point,

A particle is projected vertically upwards in vacuum with a speed u .

A particle is projected vertically upwards in vacuum with a speed u .

A body is projected with the velocity u_1 from the point (A) as shown in Fig. 2. (d). 37. At the same time another body is projected vertically upwards with the velocity u_2 from the point (B) .What should be the value of u_1//u_1 for both the bodies to collide ? .

A body is projected vertically upwards with a velocity 'U'. It crosses a point in its journey at a height 'h' twice, just after 1 and 7 seconds. The value of U in ms^(-1) [ g=10 ms^(-2) ]