An alternating emf given by equation
`e=300sin(100pi)t V`
is applied to a resistance `100 Omega`. The rms current through the circuit is (in amperes).

An alternating emf given by equation E=300sin[(100π)t] volt is applied to a resistance 100 ohms. Find the rms current through the circuit.

An alternating emf, e=300 sin100 pit volt, is applied to a pure resistance of 100 Omega . The rms current through the circuit is

An alternating e.m.f., e = 300 sin 100 pi t volt, is applied to a pure resistance of 100 Omega . The r.m.s. current through the cicuit is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-r.m.s. current through the circuit

An alternating e.m.f. is given by 100 sin 100 pi t to a pure resistance of 50 Omega . calculate:- r.m.s current through the circuit.

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-frequency

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:- power dissipated in the circuit.

An alternating e.m.f. is given by 100 sin 100 pi t to a pure resistance of 50 Omega . calculate:-frequency

A alternating e.m.f. e = 200 sin (100 pit) is connected across a resistor of resistance 10 Omega . Calculate the r.m.s. current flowing through the circuit.