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int (cos7x-cos8x)/(1+2cos5x)dx...

`int (cos7x-cos8x)/(1+2cos5x)dx`

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int(cos7x-cos8x)/(1+2cos 5x)dx=

int(cos8x-cos7x)/(1+2cos5x)dx

The value of int (cos 7x-cos 8x)/(1+2 cos 5x)dx , is

int(cos7x-cos8x)/(cos2x-cos3x)dx

int(cos7x-cos8x)/(cos2x-cos3x)dx

If int((cos8x-cos7x)/(1+2cos5x))dx=(sin3x)/a-(sin2x)/b+c then the last digit of (a^b)^4 must be

int(cos x-cos2x)/(1-cos x)*dx

int(cos5x+cos4x)/(1-2cos3x)dx

int(cos5x+cos4x)/(1-2cos3x)dx