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Statement Equivalent weight of a species...

Statement Equivalent weight of a species can be written as molecular weight of species divided by valence factor.
Explanation Valence factor represents valence in element, acidity in bases, basicity in acids and total charge on cation or anion in an ionic compound.

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The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation Equivalent weight of MnO_(4)^(-) in acidic, basic and neutral media are in the ratio of

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation The equivalent weight of barium in BaCrO_4 used as an oxidising agent in acidic medium is (At, wt, of Ba - 137.34)

A , E, M , and n are the atomic weight equivalent weight , molecular weight and valence of an element . The correct relation is :

STATEMENT -1 : Equivalent weight of an acid is always less than its molecular weight. and STATEMENT -2 : Equivalent weight of acid = ("Molecular weight")/("n-factor")

STATEMENT -1 : Equivalent weight of an acid is always less than its molecular weight. and STATEMENT -2 : Equivalent weight of acid = ("Molecular weight")/("n-factor")

The equivalent weight of a species if acts as oxidant or reductant should be derived by: Eq. weight Mol.wt. of oxidant or reductant = ("Mol.w.t of oxidant or reductant")/("Number of electrons lost or gained by onemclecule of oxidant or reductant") . During chemical reactions, equal all equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or .n. factor The equivalent weight of an element is 13.16. It forms an acidic oxide which with KOH forms a salt isomorphous with K_(2)SO_4 The atomic weight of element is :

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. The equivalent weight of an element is 13.16 . It forms an acidic oxide which with KOH forms a salt isomorphous with K_(2)SO_(4) . The atomic weight of element is:

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of Fe_(2)O_(3) in terms of its mol. weight in the change Fe_(3)O_(4)rarrFe_(2)O_(3) is