Prove that the equation of the normal to `x^(2/3)+y^(2/3)=a^(2/3)` is `ycostheta-xsintheta=acos2theta,` where `theta` is the angle which the normal makes with the axis of `xdot`

Prove that the equation of the normal to x^((2)/(3))+y^((2)/(3))=a^((2)/(3)) is y cos theta-x sin theta=a cos2 theta where theta is the angle which the normal makes with the axis of x.

Show that the equation of the normal to x^(2/3) + y^(2/3) = a^(2/3) is y cos theta - x sin theta = a cos 2"theta" where theta is the inclination of the normal to x-axis.

The equation of normal to the curve x^(2//3)+y^(2//3)=a^(2//3) at (asin^(3) theta, a cos^(3) theta) is

The equation of normal to the curve x^(2//3)+y^(2//3)=a^(2//3) at (asin^(3) theta, a cos^(3) theta) is

The equation of the normal to the curve (x/a)^(2//3)+(y/b)^(2//3)=1 at (a cos^3theta,bsin^3theta) is

If the normal to the curve x^(2//3)+y^(2//3)=a^(2//3) makes an angle theta with the x -axis then the slope of the normal is ……….

The equation of the tangent to the curve (x/a)^(2//3)+(y/b)^(2//3)=1 at (acos^3theta,bsin^3theta) is