A force `F=ahati+bhatj+chatk` is acted upon a body of mass `m`. If the body starts from rest and was at athe origin initially, find its new coordinate after time `t`.

A force represented as shown in figure acts on a body of mass 16 kg, the body starts from rest.

A force represented as shown in figure acts on a body of mass 16 kg, the body starts from rest.

(2hati+hatj-hatk) N force is acting on a body of 10 kg mass, if the body starts from rest, then after 20 sec what will be its velocity ?

A body of mass 2 kg moves under a force of (2hati +3hatj +5hatk) N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is (Round off to the Nearest Integer)

A force vec(F) = (40 hat (i) + 10 hat(j)) N acts on body of mass 5 kg. If the body starts from rest, its position vector vec(r) at time t = 10 s, will be

(2hati+hatj-hatk) N force is acting on a body of 10 kg mass. If the body is started moving from the rest, then after 20 sec. what will be its velocity?

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then