In the formula `bar(x)=a+h(sumf_(i)u_(i))/(sumf_(i))`
for finding the mean of grouped frequency distribution `u_(i)` is equal to

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

In the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 'S and deviation from a of

In the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 'S and deviation from a of

Choose the correct answer from the given four options: In the formula x=a+(sumx_(1)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 's are the deviations from a of

If mu is the mean of a distribution , then sumf_i(y_i-mu) is equal to

Find the mean (bar(X)) if sumf_(i)x_(i)=75andsumf_(i)=15 .

In Calculating the mean of grouped data, grouped in classes of equal width, we may use the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) Where, a is the assumed mean, a must be one of the mid point of the classes. Is the last statement correct? Justify your answer.

In Calculating the mean of grouped data, grouped in classes of equal width, we may use the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) Where, a is the assumed mean, a must be one of the mid point of the classes. Is the last statement correct? Justify your answer.

Find bar(u)" if sumf_(i)u_(i)=66andsumf_(i)=100.