Stopping potential for photo electrons

In photoelectric experiment when wavelength of light is 642.4 nm falls on metal surface stopping potential of photo electron is 0.48eV. What will be the stoppingpotential when wavelength of light used is 474 nm?

The work function of potassium is 2.0 eV. When it is illuminated by light of wavelength 3300A^(@) photo electrons are emitted. The stopping potential of photo electrons is [Plank’s constant h=6.6 xx 10^(-34)Js,1eV=1.6 xx 10^(-19)J,C=3 xx 10^(8)ms^(-1) ]

The work function of potassium is 2.0 eV. When it is illuminated by light of wavelength 3300A^(@) photo electrons are emitted. The stopping potential of photo electrons is [Plank’s constant h=6.6xx10^(-34)Js,1eV=1.6xx10^(-19)J,C=3xx10^(8)ms^(-1) ]

The stopping potential for the photo electrons emitted from a metal surface of work function 1.7 eV is 10.4 V. Identify the energy levels corresponding to the transitions in hydrogen atom which will result in emission of wavelength equal to that of incident radiation for the above photoelectric effect

When monochromatic light of wavelength lambda illuminates a metal surfrce, then stopping potential for photo electric current is 3V_(0) . If wavelength changes to 2lambda then stopping potential becomes V_(0) Threshold wavelength for photo electric emission is:

The stopping potential for the photo-electrons emitted from a metal surface of work-function 1.7 eV is 10.4 eV. Find the wavelength of the radiation used. Also identify the energy-levels in hydrogen atom which will emit this wavelength.

The stopping potential for the photo-electrons emitted from a metal surface of work-function 1.7 eV is 10.4 eV. Find the wavelength of the radiation used. Also identify the energy-levels in hydrogen atom which will emit this wavelength.

What is the significance of Plank's constant in quantum theory? The stopping-potential for photo electric emission from a metallic surface is 9V,e/m = 1.8 x 10^11 c//kg . Calculate the maximum velocity of photo-electrons.

The electric field of light wave is given as vec(E )=10^(-3)cos((2pi x)/(5xx10^(-7))-2pixx6xx10^(14)t)hat(x)(N)/(C ) This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given E (in eV) = (12375)/(lambda("in"Å))

The electric field of light wave is given as vec(E)=10^(-3)cos((2 pi x)/(5xx10^(-7))-2pi xx 6xx10^(14)t) hat(x) (N)/(C) . This light falls on a metal plate of work function 2 eV. The stopping potential of the photo-electrons is: Given, E (in eV) = (12375)/(lambda ( "in" Å ))