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when 1.80 g of a nonvolatile solute is d...

when `1.80 g` of a nonvolatile solute is dissolved in `90 g` of benzene, the boiling point is raised to `354.11K`. If the boiling point of benzene is `353.23K` and `K_(b)` for benzene is `2.53 KKg mol^(-1)`, calculate the molecular mass of the solute.
Strategy: From the boiling point of the solution, calculate the boiling point elevation, `DeltaT_(b)`, then solve the equation `DeltaT_(b)=K_(b)m` for the molality `m`. Molality equals moles of solute divided by kilograms of solvent (benzene). By substituting values for molality and kilograms `C_(6)H_(6)`, we can solve for moles of solute. The molar mass of solute equals mass of solute `(1.80 g)` divided by moles of solute. The molecular mass (in amu) has the same numerical value as molar mass in `g mol^(-1)`.

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