Emergency 6.34 2. In figure 6.35, AODC ~ AOBA, Z BOC = 125 ° and LCDO = 70 °. Z DOC, LDCO And ZOAB me known. DanfDnes

In Fig. 6.35, triangleODC~triangleOBA,angleBOC=125^@ and angle CDO=70^@ Find angle DOC,angle DCO,and angle OAB .

If z_1 = (3,5) and z_2 = (2,6) find z_1 .z_2

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to

Consider the situation shown in figure-6.35. The two slits S_(1) and S_(2) placed symmetrically around the central line are illuminated by a monochromatic light of wavelength lambda . The separation between the slits is d. The light transmitted by the slits falls on a screen E_(1) placed at a distance D from the slits. The slit S_(3) is at the central line and the slit S_(4) is at a distance z from S_(3) . Another screen E_(2) is placed a further distance D away from E_(1) . Find the ratio of the maximum to minimum intensity observed on E_(2) if z is equal is : (a) (lambdaD)/(2d) " "(b) (lambdaD)/(d)" " (c )(lambdaD)/(4d)

If x = log 0.6, y = log 1.25 and z = log 3 - 2 log 2 , find the values of : (i) x + y - z (ii) 5^(x + y - z)

That the electronic configuration of ytterbium (Z = 70) is 4f&(14) 5s^(2) and of lutetium (Z) = 71) is 4 f^(14) 5 d^(1) 6 s^(2) can be explained on the basis of

Prove that the planes 12x-15y+16z-28=0, 6x + 6y -7z- 8= 0 and 2x + 35y-39z + 12 = 0 have a common line of intersection.

C is a point on the line-semgment joining the points A (4,-2,6) and B(2,-3,4), if y-coordinates of C is 0, find its z-coordinate.