`8sin^2x +3cos^2 x =5 => cotx= `

8sin^(2)x+3cos^(2)x=5rArr cot x=

Evaluate: int \ (sin^2x cos^2x)/(sin^5x+cos^3x sin^2x + sin^3x cos^2x + cos^5x)^2 \ dx

int \ (sin^2x cos^2x)/(sin^5x+cos^3x sin^2x + sin^3x cos^2x + cos^5x)^2 \ dx

Evaluate: int \ (sin^2x cos^2x)/(sin^5x+cos^3x sin^2x + sin^3x cos^2x + cos^5x)^2 \ dx

2cosx-cos3x-cos5x= ............... A) 16 cos ^(3) x sin ^(2) x B) 16 sin^(2) x cos ^(2) x C) 4 cos ^(2) x sin ^(2) x D) 4 sin ^(2) x cos ^(2)x

int (sin^6x + cos^6x)/(sin^2 x*cos^2x) dx (i) tanx+ cotx+3x+C (ii) tanx+ cotx-3x+C (iii)tanx-cotx-3x+C (iv)tanx-cotx+3x+C

Period of ( 2 sin 2x -5 cos 2x )/( 7 cos x - 8 sin x) is

Choose the correct answer int dx/(sin^2x cos^2x) =.... a) tanx+cotx+c b) tanx-cotx+c c) tanx cotx+c d) tanx-cot2x+c

if sin x +sin^2 x = 1 then cos^12 x+ 3 cos^10 x + 3 cos^8 x + cos ^6 x =