वर्गीकृत आँकड़ों का माध्य ज्ञात करने के लिए सूत्र `barx=a+h((Sigmaf_(i)u_(i))/(Sigmaf_(i)))` में `u_(i)=`

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

Fine bar( u) , if Sigma f_(i) u_(i ) 252 and Sigmaf_(i) = 420

Find bar(u)" if sumf_(i)u_(i)=66andsumf_(i)=100.

Find the correct answer from the alternative given : The formula to find mean from a grouped frequency table is barX = A + (Sigma f_(i)u_(i))/(Sigmaf_(i))xxg In the formula , u_(i) = ….

If u_(i)=(x_(i)-15)/(8), Sigma f_(i)u_(i)=20, and Sigmaf_(i)=80, barx is

The formula to find mean from a grouped frequency table is . bar(x) = a + (sumf_(i)u_(i))/(sumf_(i)) xx h . In the formula, u_(i)=.........

If Sigmaf_(i)=100,Sigmaf_(i)x_(i)=220,Sigmaf_(i)(x_(i)-barx)=104.8 then mean deviation =

If sumf_(i)=100 and(bar(u))=-0.28,"find "sumf_(i)u_(i) .