Prove that the sum to `n` terms of the series `11+103+1005+ i s(10//9)(10^n-1)+n^2dot`

Prove that the sum of n terms of the series: 11+103+1005+ i s(10)/9(10^n-1)+n^2dot

Prove that the sum to n terms of the series 11+103+1005+...is(10/9)(10^(n)-1)+n^(2)

Prove that the sum to n terms of the series 11 + 103 + 1005 + …. Is (10/9) (10^(n)-1)+n^(2) .

The sum to n terms of the series 11+103+1005+"…." is

(a) If a^(2)+2bc,b^(2)+2ac,c^(2)+2ab are in A.P ., show that (1)/(b-c),(1)/(c-a),(1)/(a-b) are in A.P . (b) Prove that the sum to n terms of the series 11+103+1005+…. = (10)/(9)(10^(n)-1)+n^(2) .

The sum to n terms of the series 11 + 103 + 1005 + …. Is

Prove that the sum of n terms of the series: 11+103+1005+...is(10)/(9)(10^(n)-1)+n^(2)

Find the sum of n terms of the series 11 + 103 + 1005 + ...

Find the sum of n terms of the series 1+4+10+20+35+…