If in a biprism experiment, light of wavelength 5000 Å is replaced by 10,000 Å, then the fringes will

Light of wavelength 5000 Å, illuminates the slit in a biprism experiment. If it is replaced by light of wavelength 6500 Å, then the fringe width will

In a biprism experiment, when sodium light of wavelength 5890 Å is used then twenty fringes are observed in 23 mm distance on screen. In order to obtain 30 fringes in 28 mm of the interference pattern, one should use light of wavelength :

In a Fresnel's biprism experiment, sodium light of wavelength 5832 Å is used. Calculated the fringe width, given the distance between the screen and the biprism =120 cm and the distance the two sources=0.04 cm.

In a biprism experiement, by using light of wavelength 5000Å , 5mm wide fringes are obtained on a screen 1.0m away from the coherent sources. The separation between the two coherent sources is

In a biprism experiement, by using light of wavelength 5000Å , 5mm wide fringes are obtained on a screen 1.0m away from the coherent sources. The separation between the two coherent sources is

The fringe width at a distance of 50 cm from the slits in young's experiment for light of wavelength 6000 Å is 0.048cm . The fringe width at the samedistance for lambda = 5000 Å will be

The fringe width in a biprims experiment is 0.32 mm, when red light of waelength 6400Å is used. If source of blue light of wavelength 4000Å is used with the same setting, then the fringe width will