A particle moving along the x axis is acted upon by a single force F = `F_0 e^(-kx)` , where `F_0` and k are constants. The particle is released from rest at x = 0. It will attain a maximum kinetic energy of :

A particle is moving along the x-axis and force acting on it is given by F=F_0sinomegaxN , where omega is a constant. The work done by the force from x=0 to x=2 will be

A particle is moving along the x-axis and force acting on it is given by F=F_0sinomega_xN , where omega is a constant. The work done by the force from x=0 to x=2 will be

A particle moving along the x- axis is subjected to a force given by F=F_(0)(e^(x//a)-1) where F_(0) and are constants Determine an expression for the work done by this force as the particle moves from the origin to the point x=r

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

A particle free to move along x-axis is acted upon by a force F=-ax+bx^(2) whrte a and b are positive constants. For ximplies0 , the correct variation of potential energy function U(x) is best represented by.

A particle is acted upon by a force given by F = - alphax^(3) -betax^(4) where alpha and beta are positive constants. At the point x = 0, the particle is –

A particle is moving along x-axis from x = 0 to x = 5 under the influence of force F = 7-2x + 3x^2 .

A particle moving along the X-axis executes simple harmonic motion, then the force acting on it is given by where, A and K are positive constants.

A particle moving along the X-axis executes simple harmonic motion, then the force acting on it is given by where, A and K are positive constants.