An alternating e.m.f. given by e=200 sin 50 t is applied to a circuit containing only a resistance of `50 Omega`. What is the value of r.m.s. current in the circuit?

An alternating emf of 200 V, 50 Hz is applied a circuit containing a resistance of 100 Omega and inductance of 0.1 H in series. The powerr dissipated in the circuit is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-frequency

An alternating e.m.f., e=200 sin omega t is applied to a lamp, whose filament has a resistance of 1000 Omega . The r.m.s. value of current is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:- power dissipated in the circuit.

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-peak value of e.m.f.

An e.m.f. e = 4 cos 1000 t volt is applied to LR circuit of inductance 3 mH and resistance 4 Omega . The amplitude of current in the circuit is

An emf E = 4 cos 1000t volt is applied to an L-R circuit of inductance 3 mH and resistance 4 Omega . The amplitude of the current in the circuit is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-r.m.s. current through the circuit

A alternating e.m.f. e = 200 sin (100 pit) is connected across a resistor of resistance 10 Omega . Calculate the r.m.s. current flowing through the circuit.