If `5 sinalpha=3"sin"(alpha+2beta)!=0,` then `tan(alpha+beta)` is equal to

If 5sin alpha=3sin(alpha+2 beta)!=0, then tan(alpha+beta) is equal to

If 5sin alpha=3(alpha+2 beta)!=0, then tan(alpha+beta) is equal to

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If 3 sin beta=sin(2alpha+beta) , then tan (alpha+beta)-2 tan alpha is

If 3sin beta = sin(2alpha + beta) , then tan(alpha + beta)-2tan alpha is:

If sin(alpha + beta) = 1 , sin(alpha - beta) = 1/2 , then : tan(alpha + 2beta)tan(2alpha + beta) is equal to :

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/2) is equal to-