In a series L-R circuit `(L=35 mH and R=11 Omega)`, a variable emf source `(V=V_(0) sin omega t)` of `V_(rms)=220V` and frequency 50 Hz is applied. Find the current amplitude in the circuit and phase of current with respect to voltage. Draw current-time graph on given graph `(pi=22/7)`.

In a series RL circuit with L=(175)/(11)mH and R=12Omega and AC source of emf e=130sqrt(2)V , 50Hz is applied. Find the circuit impedance and phase difference of EMF and current in circuit.

In a series RL circuit with L=(175)/(11)mH and R=12Omega and AC source of emf e=130sqrt(2)V , 50Hz is applied. Find the circuit impedance and phase difference of EMF and current in circuit.

An emf of V= V_0sin omegat is applied on a series LCR circuit. IF there is no phase difference between the voltage and current then,

A series circuit consisting of a capacitor with capacitance C=22 mu F and a coil with active resistance R=20 Omega and iniductance L=0.35 H is connected to a source of alternating voltage with amplitude V_(m)=180 V and frequency omega=314 s^(-1) . Find : (a) the current amplitude in the circuit, (b) the phase difference between the current and the external voltage , (c) the amplitudes of voltage across the capacitor and the coil.

Fig. show a series LCR circuit with L = 0.1 H l, X_(C ) = 14 Omega and R = 12 Omega connected to a 50 Hz, 200 V source. Calculate (i) current in the circuit and (ii) phase angle between current and voltage. Take pi = 3

A resistance of 400Omega and a capacitance of reactance 200Omega are connected in series to a 220V, 50Hz a.c source. If the current in the circuits is 0-49A. Find value of the inductance required so that voltage and current are in phase.

An L-R circuit has R = 10 Omega and L = 2H . If 120 V , 60 Hz AC voltage is applied, then current in the circuit will be

An L-R circuit has R = 10 Omega and L = 2H . If 120 V , 60 Hz AC voltage is applied, then current in the circuit will be

Figure shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80 muF , R= 40 Omega . Obtain the impedance of the circuit and the amplitude of current at the resonating frequency. :