a(b-c)-b(c-a)-c(a-b)

(a^(2)-b^(2)-2bc-c^(2))/(a^(2)+b^(2)+2ab-c^(2)) is equivalent to (a-b+c)/(a+b+c)( b) (a-b-c)/(a-b+c)(c)(a-b-c)/(a+b-c)(d)(a+b+c)/(a-b+c)

if |(b+c,a-c,a-b),(b-c,c+a,b-a),(c-b,c-a,a+b)|=k(abc) .Then k is:

|{:(b+c,a-c,a-b),(b-c,c+a,b-a),(c-b,c-a,a+b):}|=8abc

Show that |(b+c,a-c,a-b),(b-c,c+a,b-a),(c-b,c-a,a+b)|=8abc

Prove the following: [[a+b+c,-c,-b],[-c,a+b+c,-a],[-b,-a,a+b+c]] =2(b+c)(c+a)(a+b)

If in a triangle A B C angle B=90^0 then tan^2(A/2) is (b-c)/a (b) (b-c)/(b+c) (c) (b+c)/(b-c) (d) (b+c)/a

If in a triangle A B C angle B=90^0 then tan^2(A/2) is (b-c)/a (b) (b-c)/(b+c) (c) (b+c)/(b-c) (d) (b+c)/a

((a+b+c)^(a+b)(a+b+c)^(b+c)(a+b+c)^(c+a))/([(a+b+c)^(a)(a+b+c)^(b)(a+b+c)^(c)]^(2))

((a+b+c)^(a+b)(a+b+c)^(b+c)(a+b+c)^(c+a))/([(a+b+c)^(a) (a+b+c)^(b) (a+b+c)^(c)]^(2))

|(a,b-c,c+b),(a+c,b,c-a),(a-b,b+a,c)|=