[" If a ray travelling along tha line "x=1" gets reflected from the ine "x+y=1" ,then the socin "],[" line along which the reffected ray travels is "],[[" (A) "y=0," (B) "x-y=1],[" (C) "x=0," (D) none of thase "]]

If a ray travelling along the line x = 1 gets reflected from the line x + y = 1, then the eqaution the line along which the reflected ray travels is

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

If a ray travelling the line x=1 gets reflected the line x+y=1, then the equation of the line along which the reflected ray travels is

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light along the line x-2y+5=0 is reflected from the line 3x-2y+7=0.Fidn the equations of the line containing the reflected ray.

Canal rays travel in a straight line.

A light ray coming along the line 3x+4y=5 gets reflected from the line a x+b y=1 and goes along the line 5x-12 y=10. Then,

A light ray coming along the line 3x+4y=5 gets reflected from the line ax+by=1 and goes along the line 5x-12y=10. Then,

[" 16.A ray travelling along the line "3x-4y=5" after being reflected from a line " "Y" travels along the line "],[5x+12y=13" .Then the equation of the line "'l" is "],[[" 1) "x+8y=0," 2) "x-8y=0," 3) "32x+4y+65=0," 4) "32x-4y+65=0]]